(5x^2+x-1)(x^2+1)=0

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Solution for (5x^2+x-1)(x^2+1)=0 equation: 


Simplifying
(5x2 + x + -1)(x2 + 1) = 0

Reorder the terms:
(-1 + x + 5x2)(x2 + 1) = 0

Reorder the terms:
(-1 + x + 5x2)(1 + x2) = 0

Multiply (-1 + x + 5x2) * (1 + x2)
(-1(1 + x2) + x(1 + x2) + 5x2 * (1 + x2)) = 0
((1 * -1 + x2 * -1) + x(1 + x2) + 5x2 * (1 + x2)) = 0
((-1 + -1x2) + x(1 + x2) + 5x2 * (1 + x2)) = 0
(-1 + -1x2 + (1 * x + x2 * x) + 5x2 * (1 + x2)) = 0
(-1 + -1x2 + (1x + x3) + 5x2 * (1 + x2)) = 0
(-1 + -1x2 + 1x + x3 + (1 * 5x2 + x2 * 5x2)) = 0
(-1 + -1x2 + 1x + x3 + (5x2 + 5x4)) = 0

Reorder the terms:
(-1 + 1x + -1x2 + 5x2 + x3 + 5x4) = 0

Combine like terms: -1x2 + 5x2 = 4x2
(-1 + 1x + 4x2 + x3 + 5x4) = 0

Solving
-1 + 1x + 4x2 + x3 + 5x4 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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